Author: Michael
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A second post
$latex i\hbar\frac{\partial}{\partial t}\left|\Psi(t)\right>=H\left|\Psi(t)\right>$ [math]x^2+y^2[/math]
Data Scientist
$latex i\hbar\frac{\partial}{\partial t}\left|\Psi(t)\right>=H\left|\Psi(t)\right>$ [math]x^2+y^2[/math]